/**
* alphaNumericPlaindrome should return true if the string has alphanumeric characters that are palindrome irrespective of special characters and the letter case
* @param {string} str the string to check
* @returns `Boolean`
*/
/*****************************************************************************
* What is a palindrome? https://en.wikipedia.org/wiki/Palindrome
*
* The function alphaNumericPlaindrome() receives a string with varying formats
* like "racecar", "RaceCar", and "race CAR"
* The string can also have special characters
* like "2A3*3a2", "2A3 3a2", and "2_A3*3#A2"
*
* But the catch is, we have to check only if the alphanumeric characters
* are palindrome i.e remove spaces, symbols, punctuations etc
* and the case of the characters doesn't matter
*
* This is one of the questions/projects that we have to solve for the
* JavaScript Algorithms and Data Structures course on https://www.freecodecamp.org
*
* Author -- Syed Fasiuddin
* https://github.com/SyedFasiuddin
*
****************************************************************************/
const alphaNumericPlaindrome = (str) => {
// removing all the special characters and turning everything to lowercase
const newStr = str.replace(/[^a-zA-Z0-9]*/g, '').toLowerCase()
// the newStr variable is a string and only has alphanumeric characters all in lowercase
// making an array of individual characters as it's elements
const arr = newStr.split('')
// setting a variable to see if change occurs to it
let palin = 0
// making a copy of arr with spread operator
const arrRev = [...arr]
// you can use arrRev.reverse() to reverse the array
// or else you can use the below method
// iterate through the arr and check the condition of palindrome
for (let i = 0; i < arr.length; i++) {
if (arr[i] !== arrRev[arr.length - 1 - i]) {
// if the string is not palindrome then we change palin variable to 1
palin = 1
}
}
// if the string is palindrome then palin variable is never changed
if (palin === 0) return true
else return false
}
export { alphaNumericPlaindrome }